At relatively high pressure,van der Waals' eq | vedclass

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(C) The van der Waals equation for $1$ mole of gas is given by: $\left(P + \frac{a}{V^2}\right)(V - b) = RT$. At relatively high pressure,the volume $

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$PV = RT + Pb$

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(C) The van der Waals equation for $1$ mole of gas is given by: $\left(P + \frac{a}{V^2}\right)(V - b) = RT$. At relatively high pressure,the volume $V$ is small,making the pressure correction term $\frac{a}{V^2}$ negligible compared to $P$. However,the volume correction term $b$ remains significant. Thus,the equation simplifies to: $P(V - b) = RT$. Expanding this,we get: $PV - Pb = RT$,which rearranges to $PV = RT + Pb$. Therefore,option $C$ is correct.

At relatively high pressure,van der Waals' equation becomes

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